Hi all,
Attached is the marginal values for the above problem solved using two solvers,
using SBB (licensed):
Simple B&B Sep 3, 2003 WIN.SB.SB 21.2 011.026.041.VIS
Relaxed problem gives integer solution.
---- EQU SOC_batt Battery soc level
LOWER LEVEL UPPER MARGINAL
1 0.495 0.495 0.495 EPS
2 . . . EPS
---- EQU Ptotal total power supplied
LOWER LEVEL UPPER MARGINAL
1 10.000 10.000 10.000 EPS
2 20.000 20.000 20.000 EPS
LOWER LEVEL UPPER MARGINAL
---- EQU obj 501.788 501.788 501.788 1.000
---- VAR Ptot total flow
LOWER LEVEL UPPER MARGINAL
1 . 10.000 30.000 .
2 . 20.000 30.000 .
---- VAR soc SOC of battery
LOWER LEVEL UPPER MARGINAL
1 0.200 0.495 0.800 .
2 0.200 0.490 0.800 .
LOWER LEVEL UPPER MARGINAL
---- VAR Z -INF 501.788 +INF .
Z obj function
---- VAR P_Batt Battery output
LOWER LEVEL UPPER MARGINAL
1 . . 40.000 EPS
2 . . 40.000 EPS
---- VAR U_Batt
LOWER LEVEL UPPER MARGINAL
1 -1.000 . 1.000 EPS
2 -1.000 . 1.000 EPS
**** REPORT SUMMARY : 0 NONOPT
0 INFEASIBLE
0 UNBOUNDED
0 ERRORS
EXECUTION TIME = 0.000 SECONDS 0.8 Mb WIN212-136
using BARON (demo):
Baron 5.0 Sep 3, 2003 WIN.BA.NA 21.2 005.000.000.VIS P3PC
Branch And Reduce Optimization Navigator
Nikolaos Sahinidis and Mohit Tawarmalani
The Optimization Firm, LLC.
Total time elapsed : 000:00:00, in seconds: 0.02
on parsing : 000:00:00, in seconds: 0.00
on preprocessing: 000:00:00, in seconds: 0.02
on navigating : 000:00:00, in seconds: 0.00
on relaxed : 000:00:00, in seconds: 0.00
on local : 000:00:00, in seconds: 0.00
on tightening : 000:00:00, in seconds: 0.00
on marginals : 000:00:00, in seconds: 0.00
on probing : 000:00:00, in seconds: 0.00
Total no. of BaR iterations: 1
Best solution found at node: 1
Max. no. of nodes in memory: 1
Solution = 800.004 found at node 1
Best possible = 800.004
Absolute gap = 0 optca = 0
Relative gap = 0.00000 optcr = 0.1
— Using CONOPT to complete solution
CONOPT iterations = 4
CONOPT time = 0.055 seconds
CONOPT max rmove = 7.76E-07
CONOPT rel norm2 = 9.21E-07
---- EQU SOC_batt Battery soc level
LOWER LEVEL UPPER MARGINAL
1 0.495 0.495 0.495 680.000
2 . . . 686.869
---- EQU Ptotal total power supplied
LOWER LEVEL UPPER MARGINAL
1 10.000 10.000 10.000 EPS
2 20.000 20.000 20.000 -9.899
LOWER LEVEL UPPER MARGINAL
---- EQU obj 501.788 501.788 501.788 1.000
---- VAR Ptot total flow
LOWER LEVEL UPPER MARGINAL
1 . 19.822 30.000 .
2 . 30.000 30.000 9.899
---- VAR soc SOC of battery
LOWER LEVEL UPPER MARGINAL
1 0.200 0.351 0.800 .
2 0.200 0.200 0.800 -686.869
LOWER LEVEL UPPER MARGINAL
---- VAR Z -INF 800.004 +INF .
Z obj function
---- VAR P_Batt Battery output
LOWER LEVEL UPPER MARGINAL
1 . 9.822 40.000 .
2 . 10.000 40.000 .
---- VAR U_Batt
LOWER LEVEL UPPER MARGINAL
1 -1.000 -1.000 1.000 168.162
2 -1.000 -1.000 1.000 172.945
**** REPORT SUMMARY : 0 NONOPT
0 INFEASIBLE
0 UNBOUNDED
0 ERRORS
EXECUTION TIME = 0.000 SECONDS 0.8 Mb WIN212-136
I think while using SBB the integer variables are remaining at 0. Can anyone give any insight about it?
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