how to code the position of last element in a set

Archiver · January 19, 2016, 3:13pm

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu

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Archiver · January 19, 2016, 3:22pm

hallo,

i mean the element in a set is infinity.

Thank you!> å†™é“ï¼š

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu

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Archiver · January 19, 2016, 3:58pm

Hi Yu

Use card(i) which will give you the cardinality of the set (the number of elements)

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu

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Archiver · January 19, 2016, 4:15pm

hi Renger,

I want to defind the order of the element. I show you my example:

my code:

NB5(i,l)$(ord(l)>1 and ord(l)1 and ord(l) å†™é“ï¼š

Hi Yu
Use card(i) which will give you the cardinality of the set (the number of elements)
Cheers
Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu

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Archiver · January 19, 2016, 4:25pm

NB5(i,l)$(ord(l)>1 and ord(i) 1 and ord(l)1 and ord(l) å†™é“ï¼š

Hi Yu

Use card(i) which will give you the cardinality of the set (the number of elements)

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu

–
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Archiver · January 20, 2016, 9:48am

hi Renger,

thank you for you help, but i donâ€™t unterstand , why hier is ord(i) å†™é“ï¼š

NB5(i,l)$(ord(l)>1 and ord(i) Cheers
Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Dienstag, 19. Januar 2016 16:15
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

I want to defind the order of the element. I show you my example:

my code:

NB5(i,l)(ord(l)>1 and ord(l) NB6(i,l)(ord(l)>1 and ord(l)
In there 1 ist the number of order for the first element, is the order number for the last one.

some advice. Thank you!

Best regards

Yu
åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ15:58ï¼ŒRenger van Nieuwkoop å†™é“ï¼š
Hi Yu
Use card(i) which will give you the cardinality of the set (the number of elements)
Cheers
Renger

From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu
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Archiver · January 20, 2016, 10:56am

Yes, it should be.

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Mittwoch, 20. Januar 2016 09:49
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

thank you for you help, but i donâ€™t unterstand , why hier is ord(i) å†™é“ï¼š

NB5(i,l)(ord(l)>1 and ord(i) \ \ \ my code: \ \ \ NB5(i,l)(ord(l)>1 and ord(l)1 and ord(l) is the order number for the last one.

some advice. Thank you!

Best regards

Yu

åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ15:58ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Hi Yu

Use card(i) which will give you the cardinality of the set (the number of elements)

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu

–
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Archiver · January 20, 2016, 10:57am

hi Renger,

thank you very much again!

Yu
åœ¨ 2016å¹´1æœˆ20æ—¥ï¼Œ10:56ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Yes, it should be.
Cheers
Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Mittwoch, 20. Januar 2016 09:49
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

thank you for you help, but i donâ€™t unterstand , why hier is ord(i)
Best regards

Yu
åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ16:25ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

NB5(i,l)$(ord(l)>1 and ord(i)      Cheers
Renger

From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>]
Sent: Dienstag, 19. Januar 2016 16:15
To: <gamsworld@googlegroups.com>
Subject: Re: how to code the position of last element in a set

hi Renger,

I want to defind the order of the element. I show you my example:


my code:

NB5(i,l)$(ord(l)>1 and ord(l)     NB6(i,l)$(ord(l)>1 and ord(l)
In there 1 ist the number of order for the first element,  is the order number for the last one.

some advice. Thank you!

Best regards

Yu
åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ15:58ï¼ŒRenger van Nieuwkoop  å†™é“ï¼š



    Hi Yu
    Use card(i) which will give you the cardinality of the set (the number of elements)
    Cheers
    Renger

    From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>] On Behalf Of Yu Li
    Sent: Dienstag, 19. Januar 2016 15:14
    To: gamsworld
    Subject: how to code the position of last element in a set

    Hallo,

    the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

    Thanks in advance.

    Yu
    --
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Archiver · January 22, 2016, 6:58pm

hi Renger,

can you please help me again, how can i write the code for output the number of Iteration for some certain model, is there an option for this or some easy way?

Thank you!

yu
åœ¨ 2016å¹´1æœˆ20æ—¥ï¼Œ10:56ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Yes, it should be.
Cheers
Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Mittwoch, 20. Januar 2016 09:49
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

thank you for you help, but i donâ€™t unterstand , why hier is ord(i)
Best regards

Yu
åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ16:25ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

NB5(i,l)$(ord(l)>1 and ord(i)      Cheers
Renger

From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>]
Sent: Dienstag, 19. Januar 2016 16:15
To: <gamsworld@googlegroups.com>
Subject: Re: how to code the position of last element in a set

hi Renger,

I want to defind the order of the element. I show you my example:


my code:

NB5(i,l)$(ord(l)>1 and ord(l)     NB6(i,l)$(ord(l)>1 and ord(l)
In there 1 ist the number of order for the first element,  is the order number for the last one.

some advice. Thank you!

Best regards

Yu
åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ15:58ï¼ŒRenger van Nieuwkoop  å†™é“ï¼š



    Hi Yu
    Use card(i) which will give you the cardinality of the set (the number of elements)
    Cheers
    Renger

    From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>] On Behalf Of Yu Li
    Sent: Dienstag, 19. Januar 2016 15:14
    To: gamsworld
    Subject: how to code the position of last element in a set

    Hallo,

    the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

    Thanks in advance.

    Yu
    --
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Archiver · January 25, 2016, 12:33pm

Hi Yu

You can the iterations used to solve a model by storing yourmodelname.iterusd in a parameter.

e.g.

model test /all/;

solve testâ€¦

parameter iterationsused;

iterationsused = test.iterusd;

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Freitag, 22. Januar 2016 18:59
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

can you please help me again, how can i write the code for output the number of Iteration for some certain model, is there an option for this or some easy way?

Thank you!

yu

åœ¨ 2016å¹´1æœˆ20æ—¥ï¼Œ10:56ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Yes, it should be.

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Mittwoch, 20. Januar 2016 09:49
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

thank you for you help, but i donâ€™t unterstand , why hier is ord(i) å†™é“ï¼š

NB5(i,l)(ord(l)>1 and ord(i) \ \ \ my code: \ \ \ NB5(i,l)(ord(l)>1 and ord(l)1 and ord(l) is the order number for the last one.

some advice. Thank you!

Best regards

Yu

åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ15:58ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Hi Yu

Use card(i) which will give you the cardinality of the set (the number of elements)

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu

–
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Archiver · January 25, 2016, 1:04pm

hi Renger,

thank you so much, you are my god.

best regards

Yu Li
åœ¨ 2016å¹´1æœˆ25æ—¥ï¼Œ12:33ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Hi Yu

You can the iterations used to solve a model by storing yourmodelname.iterusd in a parameter.

e.g.
model test /all/;
solve testâ€¦
parameter iterationsused;
iterationsused = test.iterusd;
Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Freitag, 22. Januar 2016 18:59
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

can you please help me again, how can i write the code for output the number of Iteration for some certain model, is there an option for this or some easy way?

Thank you!

yu
åœ¨ 2016å¹´1æœˆ20æ—¥ï¼Œ10:56ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Yes, it should be.
Cheers
Renger

From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>]
Sent: Mittwoch, 20. Januar 2016 09:49
To: <gamsworld@googlegroups.com>
Subject: Re: how to code the position of last element in a set

hi Renger,

thank you for you help, but i donâ€™t unterstand , why hier is ord(i)
Best regards

Yu
åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ16:25ï¼ŒRenger van Nieuwkoop  å†™é“ï¼š



    NB5(i,l)$(ord(l)>1 and ord(i)          Cheers
    Renger

    From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>]
    Sent: Dienstag, 19. Januar 2016 16:15
    To: <gamsworld@googlegroups.com>
    Subject: Re: how to code the position of last element in a set

    hi Renger,

    I want to defind the order of the element. I show you my example:


    my code:

    NB5(i,l)$(ord(l)>1 and ord(l)         NB6(i,l)$(ord(l)>1 and ord(l)
    In there 1 ist the number of order for the first element,  is the order number for the last one.

    some advice. Thank you!

    Best regards

    Yu
    åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ15:58ï¼ŒRenger van Nieuwkoop  å†™é“ï¼š




        Hi Yu
        Use card(i) which will give you the cardinality of the set (the number of elements)
        Cheers
        Renger

        From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>] On Behalf Of Yu Li
        Sent: Dienstag, 19. Januar 2016 15:14
        To: gamsworld
        Subject: how to code the position of last element in a set

        Hallo,

        the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

        Thanks in advance.

        Yu
        --
        To unsubscribe from this group and stop receiving emails from it, send an email to <gamsworld+unsubscribe@googlegroups.com>.
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Archiver · January 25, 2016, 1:44pm

hi Renger,

I attach my Codes, i have already put the Option in my codes, but it doesâ€™t work.
I want to count the total iteration for model Relaxation within the iteration what i defined( 50iterations).
Cound you help me?

best regards

Yu Li

*Subgradientenverfahren fÃ¼r Stufenrabatten
$eolcom //
sets

i Lieferanten /L1L4/
l Rabattstufen /R1R4/ ;
alias(i,ii);

Table P(i,l) Preis

R1 R2 R3 R4
L1 50 48 45 40
L2 48 45 43 40
L3 49 45 44 41
L4 47 44 40 37;

Table QU(i,l) Untergrenzen von Rabattstufe

R1 R2 R3 R4
L1 30 60 100 200
L2 40 80 120 220
L3 30 70 130 210
L4 20 40 60 150;

Table QO(i,l) Obergrenzen von Rabattstufe

R1 R2 R3 R4
L1 60 100 200 10000
L2 80 120 220 10000
L3 70 130 210 10000
L4 40 60 150 10000;

Parameters

QM(i) maximale Lieferraten

/L1 28
L2 20
L3 15
L4 30/

K(i) fixe Lieferkosten

/L1 120
L2 110
L3 115
L4 110/

lambda(i) Lagrange-Multiplikatoren

h(i,l) LagerungskostensÃ¤tze ;

Scalars d Rest-Bedarf pro Periode
orig_d ursprÃ¼nglicher Bedarf pro Periode /35/
lz Lagerzinssatz /0.03/;

Variables

Lagrange Wert der Lagrange-Funktion
q(i,l) Bestellmenge
sq gesamte Bestellmenge
y(i,l) binaere Indikatorvariable fuer q>0 ;

sq.lo = 1; // zur Vermeidung numerischer InstabilitÃ¤t

Positive variable q;
Binary variable y;

Parameter flag(i) 1 wenn Lieferant i noch untersucht wird ;
flag(i)=1;

Equations
LR Definition Lagrange-Funktion
NB1 Bedarfdsrestriktion
NB2(i,l) Untergrenze von Bestellmenge
NB3(i,l) Obergrenze von Bestellmenge
NB4(i) Eindeutigkeit ;

LR… Lagrange =e= sum((i,l)$flag(i), p(i,l)*q(i,l)d/sq + h(i,l) q(i,l)/2 + K(i)*y(i,l)*d/sq);
NB1… sq =e= sum((i,l)$flag(i), q(i,l));
NB2(i,l)$flag(i)… q(i,l) =g= QU(i,l)*y(i,l) ;
NB3(i,l)$flag(i)… q(i,l) =l= QO(i,l)*y(i,l) ;
NB4(i)$flag(i)… sum(l, y(i,l)) =l= 1 ;

Model relaxation /LR, NB1, NB2, NB3, NB4/ ;

Set Iteration /iter1*iter50/;

Scalars end zeigt an ob Heuristik beendet ist /0/
converged zeigt an ob Subgradientenverfahren konvergiert ist
epsilon Toleranz fÃ¼r Abbruch des Subgradientenverfahrens /1/
sigma Schrittweite
sigma_hat Anfangswert der Schrittweite /1/ ;

Parameter alpha(i) Liefermengenanteile der Lieferanten i ;

Parameter selected(i) zeigt an ob bei Lieferant i eingekauft wird ;
selected(i)=0;

Option optcr=0;
Option minlp = baron;

// Heuristik
d = orig_d ;
while(not end,

lambda(i)=0 ;
sigma=sigma_hat ;
h(i,l)=lz*p(i,l) ;
converged = 0 ;
loop(iteration$(not converged), // Subgradientenverfahren

solve relaxation using minlp minimizing Lagrange ;
display q.l ;

sigma=sigma_hat/ord(iteration) ;

lambda(i)$flag(i)=max(0, lambda(i)+sigma*(sum(l, d*q.l(i,l))-QM(i)*sq.l)) ;
display lambda;

loop(i$flag(i),
if (lambda(i)0)) = QM(i)/orig_d ;

// letzte Iteration: LÃ¶sung der Lagrange-Relaxation ist zulÃ¤ssig, d.h. lambda(i)=0 fÃ¼r alle i
if (sum(i$flag(i), lambda(i)) = 0,
end = 1;
loop(i$flag(i),
if (sum(l, q.l(i,l))>1e-4,//warum 1e-4
alpha(i)=1-sum(ii$selected(ii), alpha(ii));
selected(i)=1;
);
);
);

display alpha ;
selected(i)(flag(i) and (lambda(i)>0)) = 1 ; flag(i)(flag(i) and (lambda(i)>0)) = 0 ;

d = d - sum(i$(lambda(i)>0), qm(i)) ;
if (d = 0, end = 1) ;
display d ;
);

Parameter An Anzahl der Iteration fÃ¼r Modell Relaxation;
An=Relaxation.iterusd ;
display An;

Variables

qq(i,l) Bestellmenge
z(i,l) Binaere Indikatorvariable fuer q>0
sqq gesamte Bestellmenge
total_cost Gesamtkosten ;

sqq.lo=1;

Positive variable qq;
Binary variable z;

Equations
cost Gesamtkosten
NB6(i) Eindeutigkeit
NB7(i,l) Untergrenze von Bestellmenge
NB8(i,l) Obergrenze von Bestellmenge
NB9(i) Maximale Liefermenge;

cost… total_cost =e= sum(i$selected(i), (alpha(i)*orig_d + alpha(i)lz/2sqq)*sum(l, p(i,l)*z(i,l)) + K(i)*orig_d/sqq) ;

NB6(i)(selected(i)).. sum(l, z(i,l)) =l= 1 ; NB7(i,l)(selected(i))… qq(i,l) =g= QU(i,l)*z(i,l) ;
NB8(i,l)(selected(i)).. qq(i,l) =l= QO(i,l)*z(i,l) ; NB9(i)(selected(i))… sum(l, qq(i,l)) =e= alpha(i)*sqq ;

Model opt_q /cost, NB6, NB7, NB8, NB9/;
sqq.lo = smax(i$selected(i), QU(i,“R1”)/alpha(i)) ;

Solve opt_q using minlp minimizing total_cost ;
Display qq.l, sqq.l, z.l, total_cost.l ;

åœ¨ 2016å¹´1æœˆ25æ—¥ï¼Œ12:33ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Hi Yu

You can the iterations used to solve a model by storing yourmodelname.iterusd in a parameter.

e.g.
model test /all/;
solve testâ€¦
parameter iterationsused;
iterationsused = test.iterusd;
Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Freitag, 22. Januar 2016 18:59
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

can you please help me again, how can i write the code for output the number of Iteration for some certain model, is there an option for this or some easy way?

Thank you!

yu
åœ¨ 2016å¹´1æœˆ20æ—¥ï¼Œ10:56ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Yes, it should be.
Cheers
Renger

From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>]
Sent: Mittwoch, 20. Januar 2016 09:49
To: <gamsworld@googlegroups.com>
Subject: Re: how to code the position of last element in a set

hi Renger,

thank you for you help, but i donâ€™t unterstand , why hier is ord(i)
Best regards

Yu
åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ16:25ï¼ŒRenger van Nieuwkoop  å†™é“ï¼š



    NB5(i,l)$(ord(l)>1 and ord(i)          Cheers
    Renger

    From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>]
    Sent: Dienstag, 19. Januar 2016 16:15
    To: <gamsworld@googlegroups.com>
    Subject: Re: how to code the position of last element in a set

    hi Renger,

    I want to defind the order of the element. I show you my example:


    my code:

    NB5(i,l)$(ord(l)>1 and ord(l)         NB6(i,l)$(ord(l)>1 and ord(l)
    In there 1 ist the number of order for the first element,  is the order number for the last one.

    some advice. Thank you!

    Best regards

    Yu
    åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ15:58ï¼ŒRenger van Nieuwkoop  å†™é“ï¼š




        Hi Yu
        Use card(i) which will give you the cardinality of the set (the number of elements)
        Cheers
        Renger

        From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>] On Behalf Of Yu Li
        Sent: Dienstag, 19. Januar 2016 15:14
        To: gamsworld
        Subject: how to code the position of last element in a set

        Hallo,

        the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

        Thanks in advance.

        Yu
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Archiver · January 25, 2016, 3:44pm

If you want to know when your loop ends, you have to define a parameter and store this number in this parameter

Parameter

loopnr /0/,

lastloopnr ;

While (â€¦…,

Loopnr = loopnr + 1

My code

);

Lastloopnr = loopnr;

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Montag, 25. Januar 2016 13:45
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

I attach my Codes, i have already put the Option in my codes, but it doesâ€™t work.

I want to count the total iteration for model Relaxation within the iteration what i defined( 50iterations).

Cound you help me?

best regards

Yu Li

*Subgradientenverfahren fÃ¼r Stufenrabatten

$eolcom //

sets

i Lieferanten /L1*L4/

l Rabattstufen /R1*R4/ ;

alias(i,ii);

Table P(i,l) Preis

R1 R2 R3 R4

L1 50 48 45 40

L2 48 45 43 40

L3 49 45 44 41

L4 47 44 40 37;

Table QU(i,l) Untergrenzen von Rabattstufe

R1 R2 R3 R4

L1 30 60 100 200

L2 40 80 120 220

L3 30 70 130 210

L4 20 40 60 150;

Table QO(i,l) Obergrenzen von Rabattstufe

R1 R2 R3 R4

L1 60 100 200 10000

L2 80 120 220 10000

L3 70 130 210 10000

L4 40 60 150 10000;

Parameters

QM(i) maximale Lieferraten

/L1 28

L2 20

L3 15

L4 30/

K(i) fixe Lieferkosten

/L1 120

L2 110

L3 115

L4 110/

lambda(i) Lagrange-Multiplikatoren

h(i,l) LagerungskostensÃ¤tze ;

Scalars d Rest-Bedarf pro Periode

orig_d ursprÃ¼nglicher Bedarf pro Periode /35/

lz Lagerzinssatz /0.03/;

Variables

Lagrange Wert der Lagrange-Funktion

q(i,l) Bestellmenge

sq gesamte Bestellmenge

y(i,l) binaere Indikatorvariable fuer q>0 ;

sq.lo = 1; // zur Vermeidung numerischer InstabilitÃ¤t

Positive variable q;

Binary variable y;

Parameter flag(i) 1 wenn Lieferant i noch untersucht wird ;

flag(i)=1;

Equations

LR Definition Lagrange-Funktion

NB1 Bedarfdsrestriktion

NB2(i,l) Untergrenze von Bestellmenge

NB3(i,l) Obergrenze von Bestellmenge

NB4(i) Eindeutigkeit ;

LR… Lagrange =e= sum((i,l)$flag(i), p(i,l)*q(i,l)d/sq + h(i,l) q(i,l)/2 + K(i)*y(i,l)*d/sq);

NB1… sq =e= sum((i,l)$flag(i), q(i,l));

NB2(i,l)$flag(i)… q(i,l) =g= QU(i,l)*y(i,l) ;

NB3(i,l)$flag(i)… q(i,l) =l= QO(i,l)*y(i,l) ;

NB4(i)$flag(i)… sum(l, y(i,l)) =l= 1 ;

Model relaxation /LR, NB1, NB2, NB3, NB4/ ;

Set Iteration /iter1*iter50/;

Scalars end zeigt an ob Heuristik beendet ist /0/

converged zeigt an ob Subgradientenverfahren konvergiert ist

epsilon Toleranz fÃ¼r Abbruch des Subgradientenverfahrens /1/

sigma Schrittweite

sigma_hat Anfangswert der Schrittweite /1/ ;

Parameter alpha(i) Liefermengenanteile der Lieferanten i ;

Parameter selected(i) zeigt an ob bei Lieferant i eingekauft wird ;

selected(i)=0;

Option optcr=0;

Option minlp = baron;

// Heuristik

d = orig_d ;

while(not end,

lambda(i)=0 ;

sigma=sigma_hat ;

h(i,l)=lz*p(i,l) ;

converged = 0 ;

loop(iteration$(not converged), // Subgradientenverfahren

solve relaxation using minlp minimizing Lagrange ;

display q.l ;

sigma=sigma_hat/ord(iteration) ;

lambda(i)$flag(i)=max(0, lambda(i)+sigma*(sum(l, d*q.l(i,l))-QM(i)*sq.l)) ;

display lambda;

loop(i$flag(i),

if (lambda(i)0)) = QM(i)/orig_d ;

// letzte Iteration: LÃ¶sung der Lagrange-Relaxation ist zulÃ¤ssig, d.h. lambda(i)=0 fÃ¼r alle i

if (sum(i$flag(i), lambda(i)) = 0,

end = 1;

loop(i$flag(i),

if (sum(l, q.l(i,l))>1e-4,//warum 1e-4

alpha(i)=1-sum(ii$selected(ii), alpha(ii));

selected(i)=1;

);

);

display alpha ;

selected(i)$(flag(i) and (lambda(i)>0)) = 1 ;

flag(i)(flag(i) and (lambda(i)>0)) = 0 ; \ \ \ d = d - sum(i(lambda(i)>0), qm(i)) ;

if (d = 0, end = 1) ;

display d ;

);

Parameter An Anzahl der Iteration fÃ¼r Modell Relaxation;

An=Relaxation.iterusd ;

display An;

Variables

qq(i,l) Bestellmenge

z(i,l) Binaere Indikatorvariable fuer q>0

sqq gesamte Bestellmenge

total_cost Gesamtkosten ;

sqq.lo=1;

Positive variable qq;

Binary variable z;

Equations

cost Gesamtkosten

NB6(i) Eindeutigkeit

NB7(i,l) Untergrenze von Bestellmenge

NB8(i,l) Obergrenze von Bestellmenge

NB9(i) Maximale Liefermenge;

cost… total_cost =e= sum(i$selected(i), (alpha(i)*orig_d + alpha(i)lz/2sqq)*sum(l, p(i,l)*z(i,l)) + K(i)*orig_d/sqq) ;

NB6(i)$(selected(i))… sum(l, z(i,l)) =l= 1 ;

NB7(i,l)$(selected(i))… qq(i,l) =g= QU(i,l)*z(i,l) ;

NB8(i,l)$(selected(i))… qq(i,l) =l= QO(i,l)*z(i,l) ;

NB9(i)$(selected(i))… sum(l, qq(i,l)) =e= alpha(i)*sqq ;

Model opt_q /cost, NB6, NB7, NB8, NB9/;

sqq.lo = smax(i$selected(i), QU(i,“R1”)/alpha(i)) ;

Solve opt_q using minlp minimizing total_cost ;

Display qq.l, sqq.l, z.l, total_cost.l ;

åœ¨ 2016å¹´1æœˆ25æ—¥ï¼Œ12:33ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Hi Yu

You can the iterations used to solve a model by storing yourmodelname.iterusd in a parameter.

e.g.

model test /all/;

solve testâ€¦

parameter iterationsused;

iterationsused = test.iterusd;

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Freitag, 22. Januar 2016 18:59
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

can you please help me again, how can i write the code for output the number of Iteration for some certain model, is there an option for this or some easy way?

Thank you!

yu

åœ¨ 2016å¹´1æœˆ20æ—¥ï¼Œ10:56ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Yes, it should be.

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Mittwoch, 20. Januar 2016 09:49
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

thank you for you help, but i donâ€™t unterstand , why hier is ord(i) å†™é“ï¼š

NB5(i,l)(ord(l)>1 and ord(i) \ \ \ my code: \ \ \ NB5(i,l)(ord(l)>1 and ord(l)1 and ord(l) is the order number for the last one.

some advice. Thank you!

Best regards

Yu

åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ15:58ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Hi Yu

Use card(i) which will give you the cardinality of the set (the number of elements)

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu

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\

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\

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Archiver · January 25, 2016, 4:10pm

hi Renger,

i added it in my code, but it returns wrong number, could you look it for me, thank you!Thank you!

Yu

Parameter loopnr /0/
Parameter lastloopnr ;

Option optcr=0;
Option minlp = baron;

// Heuristik
d = orig_d ;
while(not end,

Loopnr = loopnr + 1;
lambda(i)=0 ;
sigma=sigma_hat ;
h(i,l)=lz*p(i,l) ;
converged = 0 ;
loop(iteration$(not converged), // Subgradientenverfahren

solve relaxation using minlp minimizing Lagrange ;
display q.l ;

sigma=sigma_hat/ord(iteration) ;

lambda(i)$flag(i)=max(0, lambda(i)+sigma*(sum(l, d*q.l(i,l))-QM(i)*sq.l)) ;
display lambda;

loop(i$flag(i),
if (lambda(i)0)) = QM(i)/orig_d ;

// letzte Iteration: LÃ¶sung der Lagrange-Relaxation ist zulÃ¤ssig, d.h. lambda(i)=0 fÃ¼r alle i
if (sum(i$flag(i), lambda(i)) = 0,
end = 1;
loop(i$flag(i),
if (sum(l, q.l(i,l))>1e-4,//warum 1e-4
alpha(i)=1-sum(ii$selected(ii), alpha(ii));
selected(i)=1;
);
);
);

display alpha ;
selected(i)(flag(i) and (lambda(i)>0)) = 1 ; flag(i)(flag(i) and (lambda(i)>0)) = 0 ;

d = d - sum(i$(lambda(i)>0), qm(i)) ;
if (d = 0, end = 1) ;
display d ;
);

Lastloopnr = loopnr;
display lastloopnr;
åœ¨ 2016å¹´1æœˆ25æ—¥ï¼Œ15:44ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

If you want to know when your loop ends, you have to define a parameter and store this number in this parameter

Parameter
loopnr /0/,
lastloopnr ;

While (â€¦…,
Loopnr = loopnr + 1
My code
);
Lastloopnr = loopnr;

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Montag, 25. Januar 2016 13:45
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

I attach my Codes, i have already put the Option in my codes, but it doesâ€™t work.
I want to count the total iteration for model Relaxation within the iteration what i defined( 50iterations).
Cound you help me?

best regards

Yu Li

*Subgradientenverfahren fÃ¼r Stufenrabatten
$eolcom //
sets

i Lieferanten /L1L4/
l Rabattstufen /R1R4/ ;
alias(i,ii);

Table P(i,l) Preis
     R1      R2      R3      R4
L1 50 48 45 40
L2 48 45 43 40
L3 49 45 44 41
L4 47 44 40 37;

Table QU(i,l) Untergrenzen von Rabattstufe
     R1      R2      R3      R4
L1 30 60 100 200
L2 40 80 120 220
L3 30 70 130 210
L4 20 40 60 150;

Table QO(i,l) Obergrenzen von Rabattstufe
     R1      R2      R3      R4
L1 60 100 200 10000
L2 80 120 220 10000
L3 70 130 210 10000
L4 40 60 150 10000;

Parameters

QM(i) maximale Lieferraten

/L1 28
L2 20
L3 15
L4 30/

K(i) fixe Lieferkosten

/L1 120
L2 110
L3 115
L4 110/

lambda(i) Lagrange-Multiplikatoren

h(i,l) LagerungskostensÃ¤tze ;

Scalars d Rest-Bedarf pro Periode
orig_d ursprÃ¼nglicher Bedarf pro Periode /35/
lz Lagerzinssatz /0.03/;

Variables

Lagrange Wert der Lagrange-Funktion
q(i,l) Bestellmenge
sq gesamte Bestellmenge
y(i,l) binaere Indikatorvariable fuer q>0 ;

sq.lo = 1; // zur Vermeidung numerischer InstabilitÃ¤t

Positive variable q;
Binary variable y;

Parameter flag(i) 1 wenn Lieferant i noch untersucht wird ;
flag(i)=1;

Equations
LR Definition Lagrange-Funktion
NB1 Bedarfdsrestriktion
NB2(i,l) Untergrenze von Bestellmenge
NB3(i,l) Obergrenze von Bestellmenge
NB4(i) Eindeutigkeit ;

LR… Lagrange =e= sum((i,l)$flag(i), p(i,l)*q(i,l)d/sq + h(i,l) q(i,l)/2 + K(i)*y(i,l)*d/sq);
NB1… sq =e= sum((i,l)$flag(i), q(i,l));
NB2(i,l)$flag(i)… q(i,l) =g= QU(i,l)*y(i,l) ;
NB3(i,l)$flag(i)… q(i,l) =l= QO(i,l)*y(i,l) ;
NB4(i)$flag(i)… sum(l, y(i,l)) =l= 1 ;

Model relaxation /LR, NB1, NB2, NB3, NB4/ ;

Set Iteration /iter1*iter50/;

Scalars end zeigt an ob Heuristik beendet ist /0/
converged zeigt an ob Subgradientenverfahren konvergiert ist
epsilon Toleranz fÃ¼r Abbruch des Subgradientenverfahrens /1/
sigma Schrittweite
sigma_hat Anfangswert der Schrittweite /1/ ;

Parameter alpha(i) Liefermengenanteile der Lieferanten i ;

Parameter selected(i) zeigt an ob bei Lieferant i eingekauft wird ;
selected(i)=0;

Option optcr=0;
Option minlp = baron;

// Heuristik
d = orig_d ;
while(not end,
     lambda(i)=0 ;
     sigma=sigma_hat ;
     h(i,l)=lz*p(i,l) ;
     converged = 0 ;
     loop(iteration$(not converged), // Subgradientenverfahren

             solve relaxation using minlp minimizing Lagrange ;
             display q.l ;

             sigma=sigma_hat/ord(iteration) ;

             lambda(i)$flag(i)=max(0, lambda(i)+sigma*(sum(l, d*q.l(i,l))-QM(i)*sq.l)) ;
             display lambda;

             loop(i$flag(i),
                     if (lambda(i)                          else h(i,l)=lz*p(i,l)+2*(d*lambda(i)- sum(ii,lambda(ii)*QM(ii))));
             );

             if (sigma*sum(i, max(0, sum(l, d*q.l(i,l))-QM(i)*sq.l))          );

     alpha(i)$(flag(i) and (lambda(i)>0)) = QM(i)/orig_d ;

     // letzte Iteration: LÃ¶sung der Lagrange-Relaxation ist zulÃ¤ssig, d.h. lambda(i)=0 fÃ¼r alle i
     if (sum(i$flag(i), lambda(i)) = 0,
             end = 1;
             loop(i$flag(i),
                     if (sum(l, q.l(i,l))>1e-4,//warum 1e-4
                             alpha(i)=1-sum(ii$selected(ii), alpha(ii));
                             selected(i)=1;
                     );
             );
      );

     display alpha ;
     selected(i)$(flag(i) and (lambda(i)>0)) = 1 ;
     flag(i)$(flag(i) and (lambda(i)>0)) = 0 ;

     d = d - sum(i$(lambda(i)>0), qm(i)) ;
     if (d = 0, end = 1) ;
     display d ;
);

Parameter An Anzahl der Iteration fÃ¼r Modell Relaxation;
An=Relaxation.iterusd ;
display An;

Variables

qq(i,l) Bestellmenge
z(i,l) Binaere Indikatorvariable fuer q>0
sqq gesamte Bestellmenge
total_cost Gesamtkosten ;

sqq.lo=1;

Positive variable qq;
Binary variable z;

Equations
cost Gesamtkosten
NB6(i) Eindeutigkeit
NB7(i,l) Untergrenze von Bestellmenge
NB8(i,l) Obergrenze von Bestellmenge
NB9(i) Maximale Liefermenge;

cost… total_cost =e= sum(i$selected(i), (alpha(i)*orig_d + alpha(i)lz/2sqq)*sum(l, p(i,l)*z(i,l)) + K(i)*orig_d/sqq) ;

NB6(i)(selected(i)).. sum(l, z(i,l)) =l= 1 ; NB7(i,l)(selected(i))… qq(i,l) =g= QU(i,l)*z(i,l) ;
NB8(i,l)(selected(i)).. qq(i,l) =l= QO(i,l)*z(i,l) ; NB9(i)(selected(i))… sum(l, qq(i,l)) =e= alpha(i)*sqq ;

Model opt_q /cost, NB6, NB7, NB8, NB9/;
sqq.lo = smax(i$selected(i), QU(i,“R1”)/alpha(i)) ;

Solve opt_q using minlp minimizing total_cost ;
Display qq.l, sqq.l, z.l, total_cost.l ;

åœ¨ 2016å¹´1æœˆ25æ—¥ï¼Œ12:33ï¼ŒRenger van Nieuwkoop å†™é“ï¼š
Hi Yu

You can the iterations used to solve a model by storing yourmodelname.iterusd in a parameter.

e.g.
model test /all/;
solve testâ€¦
parameter iterationsused;
iterationsused = test.iterusd;
Cheers

Renger

From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>]
Sent: Freitag, 22. Januar 2016 18:59
To: <gamsworld@googlegroups.com>
Subject: Re: how to code the position of last element in a set

hi Renger,

can you please help me again, how can i write the code for output the number of Iteration for some certain model, is there an option for this or some easy way?

Thank you!

yu
åœ¨ 2016å¹´1æœˆ20æ—¥ï¼Œ10:56ï¼ŒRenger van Nieuwkoop  å†™é“ï¼š



    Yes, it should be.
    Cheers
    Renger

    From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>]
    Sent: Mittwoch, 20. Januar 2016 09:49
    To: <gamsworld@googlegroups.com>
    Subject: Re: how to code the position of last element in a set

    hi Renger,

    thank you for you help, but i donâ€™t unterstand , why hier is ord(i)
    Best regards

    Yu
    åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ16:25ï¼ŒRenger van Nieuwkoop  å†™é“ï¼š




        NB5(i,l)$(ord(l)>1 and ord(i)              Cheers
        Renger

        From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>]
        Sent: Dienstag, 19. Januar 2016 16:15
        To: <gamsworld@googlegroups.com>
        Subject: Re: how to code the position of last element in a set

        hi Renger,

        I want to defind the order of the element. I show you my example:


        my code:

        NB5(i,l)$(ord(l)>1 and ord(l)             NB6(i,l)$(ord(l)>1 and ord(l)
        In there 1 ist the number of order for the first element,  is the order number for the last one.

        some advice. Thank you!

        Best regards

        Yu
        åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ15:58ï¼ŒRenger van Nieuwkoop  å†™é“ï¼š





            Hi Yu
            Use card(i) which will give you the cardinality of the set (the number of elements)
            Cheers
            Renger

            From: <gamsworld@googlegroups.com> [mailto:<gamsworld@googlegroups.com>] On Behalf Of Yu Li
            Sent: Dienstag, 19. Januar 2016 15:14
            To: gamsworld
            Subject: how to code the position of last element in a set

            Hallo,

            the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

            Thanks in advance.

            Yu
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Archiver · January 25, 2016, 4:42pm

Hi Yu

IF you know what you want to count, you should study your loops and then you will find where to put the line with loopnr = loopnr + 1â€¦

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Montag, 25. Januar 2016 16:11
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

i added it in my code, but it returns wrong number, could you look it for me, thank you!Thank you!

Yu

Parameter loopnr /0/

Parameter lastloopnr ;

Option optcr=0;

Option minlp = baron;

// Heuristik

d = orig_d ;

while(not end,

Loopnr = loopnr + 1;

lambda(i)=0 ;

sigma=sigma_hat ;

h(i,l)=lz*p(i,l) ;

converged = 0 ;

loop(iteration$(not converged), // Subgradientenverfahren

solve relaxation using minlp minimizing Lagrange ;

display q.l ;

sigma=sigma_hat/ord(iteration) ;

lambda(i)$flag(i)=max(0, lambda(i)+sigma*(sum(l, d*q.l(i,l))-QM(i)*sq.l)) ;

display lambda;

loop(i$flag(i),

if (lambda(i)0)) = QM(i)/orig_d ;

// letzte Iteration: LÃ¶sung der Lagrange-Relaxation ist zulÃ¤ssig, d.h. lambda(i)=0 fÃ¼r alle i

if (sum(i$flag(i), lambda(i)) = 0,

end = 1;

loop(i$flag(i),

if (sum(l, q.l(i,l))>1e-4,//warum 1e-4

alpha(i)=1-sum(ii$selected(ii), alpha(ii));

selected(i)=1;

);

);

display alpha ;

selected(i)$(flag(i) and (lambda(i)>0)) = 1 ;

flag(i)(flag(i) and (lambda(i)>0)) = 0 ; \ \ \ d = d - sum(i(lambda(i)>0), qm(i)) ;

if (d = 0, end = 1) ;

display d ;

);

Lastloopnr = loopnr;

display lastloopnr;

åœ¨ 2016å¹´1æœˆ25æ—¥ï¼Œ15:44ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

If you want to know when your loop ends, you have to define a parameter and store this number in this parameter

Parameter

loopnr /0/,

lastloopnr ;

While (â€¦…,

Loopnr = loopnr + 1

My code

);

Lastloopnr = loopnr;

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Montag, 25. Januar 2016 13:45
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

I attach my Codes, i have already put the Option in my codes, but it doesâ€™t work.

I want to count the total iteration for model Relaxation within the iteration what i defined( 50iterations).

Cound you help me?

best regards

Yu Li

*Subgradientenverfahren fÃ¼r Stufenrabatten

$eolcom //

sets

i Lieferanten /L1*L4/

l Rabattstufen /R1*R4/ ;

alias(i,ii);

Table P(i,l) Preis

R1 R2 R3 R4

L1 50 48 45 40

L2 48 45 43 40

L3 49 45 44 41

L4 47 44 40 37;

Table QU(i,l) Untergrenzen von Rabattstufe

R1 R2 R3 R4

L1 30 60 100 200

L2 40 80 120 220

L3 30 70 130 210

L4 20 40 60 150;

Table QO(i,l) Obergrenzen von Rabattstufe

R1 R2 R3 R4

L1 60 100 200 10000

L2 80 120 220 10000

L3 70 130 210 10000

L4 40 60 150 10000;

Parameters

QM(i) maximale Lieferraten

/L1 28

L2 20

L3 15

L4 30/

K(i) fixe Lieferkosten

/L1 120

L2 110

L3 115

L4 110/

lambda(i) Lagrange-Multiplikatoren

h(i,l) LagerungskostensÃ¤tze ;

Scalars d Rest-Bedarf pro Periode

orig_d ursprÃ¼nglicher Bedarf pro Periode /35/

lz Lagerzinssatz /0.03/;

Variables

Lagrange Wert der Lagrange-Funktion

q(i,l) Bestellmenge

sq gesamte Bestellmenge

y(i,l) binaere Indikatorvariable fuer q>0 ;

sq.lo = 1; // zur Vermeidung numerischer InstabilitÃ¤t

Positive variable q;

Binary variable y;

Parameter flag(i) 1 wenn Lieferant i noch untersucht wird ;

flag(i)=1;

Equations

LR Definition Lagrange-Funktion

NB1 Bedarfdsrestriktion

NB2(i,l) Untergrenze von Bestellmenge

NB3(i,l) Obergrenze von Bestellmenge

NB4(i) Eindeutigkeit ;

LR… Lagrange =e= sum((i,l)$flag(i), p(i,l)*q(i,l)d/sq + h(i,l) q(i,l)/2 + K(i)*y(i,l)*d/sq);

NB1… sq =e= sum((i,l)$flag(i), q(i,l));

NB2(i,l)$flag(i)… q(i,l) =g= QU(i,l)*y(i,l) ;

NB3(i,l)$flag(i)… q(i,l) =l= QO(i,l)*y(i,l) ;

NB4(i)$flag(i)… sum(l, y(i,l)) =l= 1 ;

Model relaxation /LR, NB1, NB2, NB3, NB4/ ;

Set Iteration /iter1*iter50/;

Scalars end zeigt an ob Heuristik beendet ist /0/

converged zeigt an ob Subgradientenverfahren konvergiert ist

epsilon Toleranz fÃ¼r Abbruch des Subgradientenverfahrens /1/

sigma Schrittweite

sigma_hat Anfangswert der Schrittweite /1/ ;

Parameter alpha(i) Liefermengenanteile der Lieferanten i ;

Parameter selected(i) zeigt an ob bei Lieferant i eingekauft wird ;

selected(i)=0;

Option optcr=0;

Option minlp = baron;

// Heuristik

d = orig_d ;

while(not end,

lambda(i)=0 ;

sigma=sigma_hat ;

h(i,l)=lz*p(i,l) ;

converged = 0 ;

loop(iteration$(not converged), // Subgradientenverfahren

solve relaxation using minlp minimizing Lagrange ;

display q.l ;

sigma=sigma_hat/ord(iteration) ;

lambda(i)$flag(i)=max(0, lambda(i)+sigma*(sum(l, d*q.l(i,l))-QM(i)*sq.l)) ;

display lambda;

loop(i$flag(i),

if (lambda(i)0)) = QM(i)/orig_d ;

// letzte Iteration: LÃ¶sung der Lagrange-Relaxation ist zulÃ¤ssig, d.h. lambda(i)=0 fÃ¼r alle i

if (sum(i$flag(i), lambda(i)) = 0,

end = 1;

loop(i$flag(i),

if (sum(l, q.l(i,l))>1e-4,//warum 1e-4

alpha(i)=1-sum(ii$selected(ii), alpha(ii));

selected(i)=1;

);

);

display alpha ;

selected(i)$(flag(i) and (lambda(i)>0)) = 1 ;

flag(i)(flag(i) and (lambda(i)>0)) = 0 ; \ \ \ d = d - sum(i(lambda(i)>0), qm(i)) ;

if (d = 0, end = 1) ;

display d ;

);

Parameter An Anzahl der Iteration fÃ¼r Modell Relaxation;

An=Relaxation.iterusd ;

display An;

Variables

qq(i,l) Bestellmenge

z(i,l) Binaere Indikatorvariable fuer q>0

sqq gesamte Bestellmenge

total_cost Gesamtkosten ;

sqq.lo=1;

Positive variable qq;

Binary variable z;

Equations

cost Gesamtkosten

NB6(i) Eindeutigkeit

NB7(i,l) Untergrenze von Bestellmenge

NB8(i,l) Obergrenze von Bestellmenge

NB9(i) Maximale Liefermenge;

cost… total_cost =e= sum(i$selected(i), (alpha(i)*orig_d + alpha(i)lz/2sqq)*sum(l, p(i,l)*z(i,l)) + K(i)*orig_d/sqq) ;

NB6(i)$(selected(i))… sum(l, z(i,l)) =l= 1 ;

NB7(i,l)$(selected(i))… qq(i,l) =g= QU(i,l)*z(i,l) ;

NB8(i,l)$(selected(i))… qq(i,l) =l= QO(i,l)*z(i,l) ;

NB9(i)$(selected(i))… sum(l, qq(i,l)) =e= alpha(i)*sqq ;

Model opt_q /cost, NB6, NB7, NB8, NB9/;

sqq.lo = smax(i$selected(i), QU(i,“R1”)/alpha(i)) ;

Solve opt_q using minlp minimizing total_cost ;

Display qq.l, sqq.l, z.l, total_cost.l ;

åœ¨ 2016å¹´1æœˆ25æ—¥ï¼Œ12:33ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Hi Yu

You can the iterations used to solve a model by storing yourmodelname.iterusd in a parameter.

e.g.

model test /all/;

solve testâ€¦

parameter iterationsused;

iterationsused = test.iterusd;

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Freitag, 22. Januar 2016 18:59
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

can you please help me again, how can i write the code for output the number of Iteration for some certain model, is there an option for this or some easy way?

Thank you!

yu

åœ¨ 2016å¹´1æœˆ20æ—¥ï¼Œ10:56ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Yes, it should be.

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com]
Sent: Mittwoch, 20. Januar 2016 09:49
To: gamsworld@googlegroups.com
Subject: Re: how to code the position of last element in a set

hi Renger,

thank you for you help, but i donâ€™t unterstand , why hier is ord(i) å†™é“ï¼š

NB5(i,l)(ord(l)>1 and ord(i) \ \ \ my code: \ \ \ NB5(i,l)(ord(l)>1 and ord(l)1 and ord(l) is the order number for the last one.

some advice. Thank you!

Best regards

Yu

åœ¨ 2016å¹´1æœˆ19æ—¥ï¼Œ15:58ï¼ŒRenger van Nieuwkoop å†™é“ï¼š

Hi Yu

Use card(i) which will give you the cardinality of the set (the number of elements)

Cheers

Renger

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Yu Li
Sent: Dienstag, 19. Januar 2016 15:14
To: gamsworld
Subject: how to code the position of last element in a set

Hallo,

the position for the first element in a set we can code like this: ord(i)=1, how to code the position for the last one?

Thanks in advance.

Yu

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