Hi everyone,
I have a question according to sets.
Imagine the set n, the set i and the subset x(n,i). Is there an easy way to for the equation x(n,i+1) = x(n^-1,i)?
Here is what I mean in a more detailed way:
set n /13/
i /120/
x(n,i);
So x got 3 values. Let’s say they get some values in the time step 8:
x(1,8) = 2
x(2,8) = 5
x(3,8) = 16
No I want to attach the values in the next timestep to:
x(1,9) = 16
x(2,9) = 5
x(3,9) = 2
The change should be dependent on some conditions, but i think it is easy to do this with binary variables.
I hope you understand, what I want to do. Thanks in advance!
Cheers
What does n^-1 means in this :
x(n,i+1) = x(n^-1,i)
?
Are there always three members of n and the last and the first “exchange” each other sequentially ? ie:
x(1,1)=1
x(2,1)=2
x(3,1)=3
x(1,2)=3
x(2,2)=2
x(3,2)=1
x(1,3)=1
x(2,2)=2
x(3,3)=3
Are valid values ?
Hi cladelpiano,
n^-1 should mean, that it is the inverted value. The equation should express, when n is 3:
x(1,i+1) = x(3,i)
x(2,i+1) = x(2,i)
x(3,i+1) = x(1,i)
n is not supposed to have 3 members all the time. It represents the number of nodes for a system, so it should be flexible.
i represents the time. The values should not exchange every timestep, but dependent on the values of the binary variables chg(i+1) and dis(i+1).
Does that answer your question?
Cheers
ehh… no ?
n^-1 should mean, that it is the inverted value.
What do you mean by “inverted” ? Why is inverted(1)=3 and inverted(3)=1 ?
Is it exchanging the last and first element ? For example for n= 4
x(1,i+1) = x(4,i)
x(2,i+1) = x(2,i)
x(3,i+1) = x(3,i)
x(4,i+1) = x(1,i)