Dear Alireza
You are right. I really appreciate your help.I had this problem for about 2 months and no one could help me.
Date: Thu, 20 Aug 2015 13:26:50 +0430
Subject: Re: if 2X(i)+3X(i+1)=3 then SC(i)=1 otherwise SC(i)=0
From: alr.bahari@gmail.com
To: gamsworld@googlegroups.com
Hi
Why you say that?!! in this case you have:
SC(I)=l=1-0=1.
SC(I)=l=0.
2*(0-1)+3*(0)-0)= -2 =l=3*SC(i).
so you have SC(I)=0 from constraint 2 .
On Wed, Aug 19, 2015 at 3:56 PM, Bahman Alipour Shandiz wrote:
Dear Alireza
Thank you in advance for your help,
but there is a problem in your suggested set of constraints, if we assume x(i)=0, x(i+1)=0 then there is the chance for sc(i) to be 1. which is not right.
Date: Mon, 17 Aug 2015 18:59:41 +0430
Subject: Re: if 2X(i)+3X(i+1)=3 then SC(i)=1 otherwise SC(i)=0
From: alr.bahari@gmail.com
To: gamsworld@googlegroups.com
Hi
according to 2X(i)+3X(i+1)=3 and because of the binary variable X(I) we have
SC(I)=1 if and only if X(I)=0 and X(I+1)=1;
So try this
SC(I)=l=1-X(I).
SC(I)=l=X(I+1).
2*(X(i)-1)+3*(X(i+1)-X(I))=l=3*SC(i).
best regards
Alireza
On Sun, Aug 16, 2015 at 12:20 AM, Bahman Alipour wrote:
Dear all,
I am trying to formulate this conditional constraint,
if 2X(i)+3X(i+1)=3 then SC(i)=1 otherwise SC(i)=0
in other words : if 2A+3B=3 then C=1 otherwise C=0 A,B,C: Binary variables
Can anybody help me?
All variables are binary variables.
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