Hello all friends
I want to do the following equations in the GAMS
Please help me.
Yt=max(0,(kt-zt))
Xt={max(((zt/kt)-1),Xmin)}*zt
Best regards,
Mehrdad
–
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Dear Mehrdad
Max and Min function turn the NLP problem into DNLP. Instead, you may like to consider this approach :
http://www.gams.com/docs/FAQ/MODELING.htm#n0004583
Ù…Øمد صادق تولّلی
National University of Singapore
On Thu, Jul 28, 2011 at 11:24 PM, mehrdad bagheri wrote:
Hello all friends
I want to do the following equations in the GAMS
Please help me.
Yt=max(0,(kt-zt))
Xt={max(((zt/kt)-1),Xmin)}*zt
Best regards,
Mehrdad
To post to this group, send email to gamsworld@googlegroups.com.
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Hi
if your eqution is the form
Y(t)=…
you have to use the Smax and DNLP insted of max and NLP, respectively.
if not, you can do this by only turning the NLP problem to DNLP
problem
Alireza.b.1201@gmail.com
On Jul 28, 7:24 pm, mehrdad bagheri
wrote:
Hello all friends
I want to do the following equations in the GAMS
Please help me.
Yt=max(0,(kt-zt))
Xt={max(((zt/kt)-1),Xmin)}*zt
Best regards,
Mehrdad
\
HI!
Please, consider next
Y = (SQRT(SQR(X)) + X)/2
if X>0 Y=X
if X:
Hi
if your eqution is the form
Y(t)=…
you have to use the Smax and DNLP insted of max and NLP, respectively.
if not, you can do this by only turning the NLP problem to DNLP
problem
Alireza.b.1201@gmail.comOn Jul 28, 7:24 pm, mehrdad bagheri
wrote:Hello all friends
I want to do the following equations in the GAMS
Please help me.
Yt=max(0,(kt-zt))
Xt={max(((zt/kt)-1),Xmin)}*zt
Best regards,
Mehrdad
–
To post to this group, send email to gamsworld@googlegroups.com.
To unsubscribe from this group, send email to gamsworld+unsubscribe@googlegroups.com.
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– With kindly regards! Andre Savitsky
Andre,
There is a non-differentiability at x = 0 in your expression. I’ve been using the following expression to approximate the function f(x) = max(0,x):
f’(x,tau) = ( sqrt( sqr(x) + sqr(tau) ) + x ) / 2,
which is differentiable in all points. However, you have to care about the value for the parameter tau. An example of this approach can be find in the following work
XAVIER, A. E. . THE HYPERBOLIC SMOOTHING CLUSTERING METHOD. Pattern Recognition, v. 43, p. 731-737, 2010.
best regards,
Luiz Carlos.
On Sat, Jul 30, 2011 at 5:56 PM, Savitsky Andre wrote:
HI!
Please, consider next
Y = (SQRT(SQR(X)) + X)/2
if X>0 Y=X
if X:
Hi
if your eqution is the form
Y(t)=…
you have to use the Smax and DNLP insted of max and NLP, respectively.
if not, you can do this by only turning the NLP problem to DNLP
problem
Alireza.b.1201@gmail.comOn Jul 28, 7:24 pm, mehrdad bagheri
wrote:Hello all friends
I want to do the following equations in the GAMS
Please help me.
Yt=max(0,(kt-zt))
Xt={max(((zt/kt)-1),Xmin)}*zt
Best regards,
Mehrdad
–
To post to this group, send email to gamsworld@googlegroups.com.
To unsubscribe from this group, send email to gamsworld+unsubscribe@googlegroups.com.
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–
With kindly regards!
Andre Savitsky
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you must set a very small lower boun for x to overcome this
problem(for examole X.lo=1E-5)
best
On 7/31/11, Luiz Carlos Sousa wrote:
Andre,
There is a non-differentiability at x = 0 in your expression. I’ve been
using the following expression to approximate the function f(x) = max(0,x):f’(x,tau) = ( sqrt( sqr(x) + sqr(tau) ) + x ) / 2,
which is differentiable in all points. However, you have to care about the
value for the parameter tau. An example of this approach can be find in the
following workXAVIER, A. E. . THE HYPERBOLIC SMOOTHING CLUSTERING METHOD. Pattern
Recognition, v. 43, p. 731-737, 2010.best regards,
Luiz Carlos.On Sat, Jul 30, 2011 at 5:56 PM, Savitsky Andre wrote:
HI!
Please, consider next
Y = (SQRT(SQR(X)) + X)/2
if X>0 Y=X
if X> >> This is the same like
Y=max(0,X)Andre
30.07.2011, 12:22, “Alireza Bahari” :
Hi
if your eqution is the form
Y(t)=…
you have to use the Smax and DNLP insted of max and NLP, respectively.
if not, you can do this by only turning the NLP problem to DNLP
problem
Alireza.b.1201@gmail.comOn Jul 28, 7:24 pm, mehrdad bagheri
wrote:Hello all friends
I want to do the following equations in the GAMS
Please help me.
Yt=max(0,(kt-zt))
Xt={max(((zt/kt)-1),Xmin)}*zt
Best regards,
Mehrdad
–
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With kindly regards!
Andre Savitsky–
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