Hello everyone
I have this constraint:
sum((i,j,t),x(i,j,t)*r(j,t))
this constraint certify for each i that is negative to j
(I mean i not equal to j)
please help me to add it to the constraint.
Thank you
\
Hello everyone
I have this constraint:
sum((i,j,t),x(i,j,t)*r(j,t))
this constraint certify for each i that is negative to j
(I mean i not equal to j)
please help me to add it to the constraint.
Thank you
\
Hi
Use the to filter index
sum((i,j,t)(ord(I)Ord(J)),x(i,j,t)*r(j,t))
On Tue, Jun 19, 2012 at 5:24 AM, s gerami.p wrote:
Hello everyone
I have this constraint:
sum((i,j,t),x(i,j,t)*r(j,t))
this constraint certify for each i that is negative to j
(I mean i not equal to j)
please help me to add it to the constraint.
Thank you
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I have this constraint:
sum((i,j,t),x(i,j,t)*r(j,t))
this constraint certify for each i that is negative to j
(I mean i not equal to j)
you may use control and ord(): sum( (i,j,t) ( ord(i) ord(j) ), x(i,j,t)*r(j,t) )
HTH,
Yan
\
Hi Yan,
I was not part of this discussion but I want to know
about the working of the condition. ord(i) ord(j).
Can u please explain how it works by giving some example.
Regards,
Dharmender Y.
dddyadav@gmail.com
On Tuesday, 19 June 2012 13:25:44 UTC+5:30, Ryan Ren wrote:
\
I have this constraint:
sum((i,j,t),x(i,j,t)*r(j,t))
this constraint certify for each i that is negative to j
(I mean i not equal to j)
you may use control and ord(): sum( (i,j,t) ( ord(i) ord(j) ), x(i,j,t)*r(j,t) )
HTH,
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Hi Yan,
I was not part of this discussion but I want to know
about the working of the condition. ord(i) ord(j).
Can u please explain how it works by giving some example.
ord(i) means the order of current index in set i,
ord(i) ord(j) , means the order numbers of two different index are not equal, i.e. they are different indices.
Since we cannot compare two indices directly in GAMS, to compare the order is a workable workaround.
Note that there is a pre-requirement that i and j are identical sets.
set i /1*10/;
set t /1/;
Alias(i, j);
Parameter X(i,j,t), r(j,t), a;
X(i,j,t) = 1;
r(j,t) = 1;
sum up when (i != j)
a = sum( (i,j,t) $ ( ord(i) ord(j) ), x(i,j,t)*r(j,t) );
display a;
End of example
HTH,
Yan
\
Thnaks alot Mr. Yan.
On Mon, Jun 25, 2012 at 11:44 AM, ä»»å½¦ wrote:
Hi Yan,
I was not part of this discussion but I want to know
about the working of the condition. ord(i) ord(j).
Can u please explain how it works by giving some example.
ord(i) means the order of current index in set i,
ord(i) ord(j) , means the order numbers of two different index are not equal, i.e. they are different indices.
Since we cannot compare two indices directly in GAMS, to compare the order is a workable workaround.
Note that there is a pre-requirement that i and j are identical sets.
set i /1*10/;
set t /1/;
Alias(i, j);
Parameter X(i,j,t), r(j,t), a;
X(i,j,t) = 1;
r(j,t) = 1;
sum up when (i != j)
a = sum( (i,j,t) $ ( ord(i) ord(j) ), x(i,j,t)*r(j,t) );
display a;
End of example
HTH,
Yan
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