Azad

With your new definition you key decision is to define a single critical AV(a,b,c). You can only choose one and then this and the next two AV will be 1.

Try something like this

Binary variable AC(a,b,c) first AV that is nonzero for each a-b

AV(a,b,c) decision;

Equations â€¦…

EqSum(a,b) … sum(c, AC(a,b,c)) =L= 1;

EQ0(a,b,c) … AV(a,b,c) =G= AC(a,b,c);

EQ1(a,b,c+1) … AV(a,b,c+1) =G= AC(a,b,c);

EQ2(a,b,c+2)… AV(a,b,c+2) =G= AC(a,b,c);

## EQtot(a,b) … sum(c,AV(a,b,c) =L= 3*sum(c,AC(a,b,c));

\

Arne Stolbjerg Drud

ARKI Consulting & Development A/S

Bagsvaerdvej 246A, DK-2880 Bagsvaerd, Denmark

Phone: (+45) 44 49 03 23, email: adrud@arki.dk

From: gamsworld@googlegroups.com [mailto:gamsworld@googlegroups.com] On Behalf Of Azad

Sent: Tuesday, November 25, 2014 6:04 PM

To: gamsworld@googlegroups.com

Cc: adrud@arki.dk

Subject: Re: Defining an eqation

HI Aren tanks alot

but this EQAtion checck my binary variable at every “c” but i want it to be qualify for one time i mean just three of this variable should be equal to 1 respectively and others should be zero like that : 0 0 0 0 0 1 1 1 0 0 0

i define an another EQ in advance that allowances my variable to be 1 in just 3 time i just do not know how to set them respectively as i mention in above line.

thank you in advance

Best rearguards

On Monday, November 24, 2014 1:42:42 PM UTC+3:30, Arne Stolbjerg Drud wrote:

Hi Azad

First of all, you cannot have A refer to both a set and a variable.

Apart from that, I think you can use

EQ1(a,b,c+1)… AV(a,b,c+1) =G= AV(a,b,c);

## EQ2(a,b,c+2)… AV(a,b,c+2) =G= AV(a,b,c);

Regards

Arne

\

Arne Stolbjerg Drud

ARKI Consulting & Development A/S

Bagsvaerdvej 246A, DK-2880 Bagsvaerd, Denmark

Phone: (+45) 44 49 03 23, email: ad…@arki.dk

From: gams...@googlegroups.com [mailto:gams...@googlegroups.com] On Behalf Of Azad

Sent: Saturday, November 22, 2014 1:58 PM

To: gams...@googlegroups.com

Subject: Defining an eqation

Hi

Dear all

I want to define an equation that : if binary variable named A(a,b,c) is 1 then A(a,b,c+1) and A(a,b,c+2) be equal to 1.

I mean :

EQ(a,b,c)… A(a,b,c)+A(a,b,(c+1) ) + A(a,b,(c+2) ) =3 ;

and C is a set /1*24/

But when i write my code as above error 145 happens!

how should i write this equation ??

thanks you in advance

Regards

AZAD

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